Toss a symmetric coin twice. What is the probability that both tosses will yield a head?
This is a well-known problem that anyone can solve. Namely, the probability of a head in each toss is 1/2, so the probability of two consecutive heads is 1/2 · 1/2 = 1/4.
BUT! What did we do? What is involved in the solution? What are the arguments behind our computations? Why did we multiply the two halves connected with each toss?
617 pàg
Peso: 3 mb
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Autor: Allan Gut



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